IF either bit = 1 (points right),
THEN intercept a red ball,
ELSE intercept a blue ball.
in other words
Catch a blue ball
both bits = 1 (they point to the right).
[Puzzle #36](Share URL: https://www.lodev.org/jstumble/?board=rle00eerxlfxxflireeleerelfrrfelrflereelee_8_8)
NOTE: Iachi found this solution in Sep 2018. So they are at least two years ahead of me. See [Puzzle 36 - Symmetrical with 22 parts]