Is it possible to make it so that you press blue as many times as you want so that it sets a number then the same for red, then it adds those numbers together.
Why wouldn’t a counter solve this? Have both the blue and the red feed into a counter. You hit blue as many times as you’d like. Then red. The bits shown will display the sum. Or, were you thinking of something else?
I was thinking for you to have one counter on each side. Like this but the numbers chosen by the number of times you press the lever.
Why not replace the crossover with an interceptor? Then each counter will show how many times you’ve pushed the corresponding lever. But then you need a way of adding these. I think this might be possible if you have a gear bit at the top of the board corresponding to “load”, which if initially pointing to the left would make the mechanism count red and blue - much like what you have now (if you add the interceptor like I mentioned). But if the gear bit were pointing to the right, it would direct the ball to another mechanism that added the two loaded values. If this is the kind of thing you’re thinking of, I’ll give it a shot.
The other idea, much simpler, is not to intercept the red and blue balls that feed the two counters, but direct them both to a third counter below the two counters, which keeps track of the number of all balls (which is the sum of blue and red). So, at the end of pushing the blue lever x times, and the red lever y times, you’ll have three counters, showing x, y, and x+y.
I don’t quite understand, can you please show me?
Here is the simpler idea. Push the blue trigger any number of times, up to 7. Similarly the red. (You can push them in any order, and you don’t need to push all of one color first - you can interleave the colors). After you’ve pushed x blues and y reds, the counter on the left will show the number x, the counter on the right will show the number y, and the bottom counter will show the sum x+y. Turing Tumble Simulator